Home
Class 11
PHYSICS
When forces F(1) , F(2) , F(3) are actin...

When forces `F_(1)` , `F_(2)` , `F_(3)` are acting on a particle of mass m such that `F_(2)` and `F_(3)` are mutually prependicular, then the particle remains stationary. If the force `F_(1)` is now rejmoved then the acceleration of the particle is

Text Solution

Verified by Experts

If mass 'm' is stationary under three forces
`vecF_(1)+vecF_(2)+vecF_(3)=0`
`vecF_(1) =-(vecF_(2)+vecF_(3))`
`sqrt(F_(2)^(2)+F_(3)^(2)) =F_(1)`
Obviously if `F_(1)` is removed then the mass will have
acceleration `a=sqrt(F_(2)^(2)+F_(3)^(2))/(m)(or)a = (F_(1))/(m)` .
Promotional Banner

Topper's Solved these Questions

  • NEWTONS LAWS OF MOTION

    NARAYNA|Exercise C.U.Q|73 Videos
  • NEWTONS LAWS OF MOTION

    NARAYNA|Exercise LEVEL -I (C.W)|47 Videos
  • MOTION IN A STRAIGHT LINE

    NARAYNA|Exercise Level 2 H.W|29 Videos
  • OSCILLATIONS

    NARAYNA|Exercise EXERCISE - IV|41 Videos

Similar Questions

Explore conceptually related problems

When forces F_1 , F_2 , F_3 , are acting on a particle of mass m such that F_2 and F_3 are mutually perpendicular, then the particle remains stationary. If the force F_1 is now removed then the acceleration of the particle is

When force vec(F)_(1),vec(F)_(2),vec(F)_(3) are acting on a particle of mass m , the particle remains in equilibrium. If the force vec(F)_(1) is now removed then the acceleration of the particle is :

When force vec(F_(1)), vec(F_(2)),vec(F_(3))"…..."vec(F_(n)) act on a particle , the particle remains in equilibrium . If vec( F_(1)) is now removed then acceleration of the particle is

F_(1)- particle is part of

F_(1) particle of oxysome

Five forces vec(F)_(1) ,vec(F)_(2) , vec(F)_(3) , vec(F)_(4) , and vec(F)_(5) , are acting on a particle of mass 2.0kg so that is moving with 4m//s^(2) in east direction. If vec(F)_(1) force is removed, then the acceleration becomes 7m//s^(2) in north, then the acceleration of the block if only vec(F)_(1) is action will be:

When a force F acts on a particle of mass m, the acceleration of particle becomes a. now if two forces of magnitude 3F and 4F acts on the particle simultaneously as shown in figure, then the acceleration of the particle is

Two forces f_(1)=4N and f_(2)=3N are acting on a particle along positve X- axis and negative y- axis respectively. The resultant force on the particle will be -

A particle of mass m is acted upon by a force F= t^2-kx . Initially , the particle is at rest at the origin. Then