Home
Class 11
PHYSICS
A body of mass 8kg is moved by a force F...

A body of mass `8kg` is moved by a force `F = (3x)N`, where x is the disatance covered Initial position is `x =2m` and final position is `x =10m` If initially the body is at rest find the final speed .

Text Solution

AI Generated Solution

To find the final speed of a body of mass \(8 \, \text{kg}\) that is moved by a force \(F = 3x \, \text{N}\), where \(x\) is the distance covered, we will follow these steps: ### Step 1: Identify the given information - Mass of the body, \(m = 8 \, \text{kg}\) - Force applied, \(F = 3x \, \text{N}\) - Initial position, \(x_i = 2 \, \text{m}\) - Final position, \(x_f = 10 \, \text{m}\) - Initial speed, \(u = 0 \, \text{m/s}\) ...
Promotional Banner

Topper's Solved these Questions

  • NEWTONS LAWS OF MOTION

    NARAYNA|Exercise C.U.Q|73 Videos
  • NEWTONS LAWS OF MOTION

    NARAYNA|Exercise LEVEL -I (C.W)|47 Videos
  • MOTION IN A STRAIGHT LINE

    NARAYNA|Exercise Level 2 H.W|29 Videos
  • OSCILLATIONS

    NARAYNA|Exercise EXERCISE - IV|41 Videos

Similar Questions

Explore conceptually related problems

An object of mass 8 kg starts to move from rest under the action of a variable force F=3xN where x is the distance (in m) covered by the object. If initially, the position of the object is x = 2 m, then find its speed ("in m s"^(-1)) when it crosses x = 10 m.

A body covers a distance of 4m under the action of force F = (17 – 4x)N where x is the distance in metres. The work done by the force is

A body covers a distance of 4m under the action of force F=(17-4x)N where x is the distance in metres. The work done by the force is

A body of mass 5kg is acted upon by a variable force. The force varies with the distance covered by the body as shown in figure. What is the speed of the body when it has covered 25m ? Assume that the body starts from rest.

A body covers a distance of 4m under the action of force F=(17-4x)N where x is the distance in metres.The work done by the force is

A body covers a distance of 4m under the action of force F=(17-4x)N where x is the distance in metres.The work done by the force is

A particle of mass m is subject to a force (F) .Find the time dependent position x(t) of the particle for the following two cases : (a) F(x)=kx, with k>0, the initial position is x_(0) , and the initial speed is zero. (b) F(v)=-bv^(2) and the initial position is zero,and the initial speed is v_(0) .

7.A particle A of mass 10/7kg is moving in the positive direction of x .Its initial position is x=0 & initial velocity is 1m/s .The velocity at x=10 is: (use the graph given)

A body of mass m = 1 kg is moving in a medium and experiences a frictional force F = -kv, where v is the speed of the body. The initial speed is v_(0) = 10 ms^(-1) and after 10 s, its energy becomes half of the initial energy. Then, the value of k is

A body of mass 2kg is moving along north-east direction with a speed sqrt(2) m/s. A force of 0.2 N is applied on the body due west for 10 sec. The final velocity ofthe body is :