A body of mas `2kg` has an initial speed `5ms^(-1)` A force acts on it for some time in the direction of motion The force-time graph is shown. Find the final speed of the body
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Explanation

Area of OA `F = (1)/(2) xx 2 xx 4 =4`
Area of ABG `F =2 xx 4 =8`
Area of `BGHC =(1)/(2) (4 +2.5) xx 0.5 = 1.625`
Area of `CDEH =2 xx 2.5 =5`
Total area under `F-t` graph =Change in momentum
`rArr m (v -u) =18.625`
`rArr v = (18.625)/(2) +5 =14.25 ms^(-1)` .