A bullet is fired from a gun The force on a bullet is `F =600 -2 xx 10^(5) t` newton. The force reduces to zero just when the bullet leaves barrel Find the impulse imparted to the bullet .

Explanation

`F =600 -2 xx 10^(5) t` F becomes zero as soon as the bullet leaves the barrel
` 0=600 -2 xx 10^(5) t rArr 600 =2 xx 10^(5) t`
`t =3 xx 10^(3) s rArr` Impulse ` =underset(0)overset(t)int Fdt`
`=underset(0)overset(t)int(600 -2 xx 10^(5)t) dt =[600t -2 xx 10^(5) (t^(2))/(2)]_(0)^(3xx10^(-3))`
`=600 xx 3 xx 10^(-3) -10^(5) xx 9 xx 10^(-6) =0.9 Ns` .