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By what acceleration the boy must go up ...

By what acceleration the boy must go up so that `100kg` block remains stationary on the wedge. The wedge is fixed and is smooth `(g =10m//s^(2))`
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Text Solution

Verified by Experts

For the block to remain stationary
`T =Mg sin theta = 100 xx 10 xx sin53`
` =100 xx 10 xx (4)/(5) = 800N`
For man `, T -mg =ma`
`T =ma (g +a) rArr 800 = 50 (10 +a) a = 6m//s^(2)` .
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