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A block is placed on an inclined plane m...

A block is placed on an inclined plane moving towards right with an acceleration `a_(0) =g` The length of the inclined plane is `l_(0)`. All the surfaces are smooth Find the time taken by the block to reach from bottom to top.
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Text Solution

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`ma = ma_(0) cos 30^(0) -mg sin 30^(0)`
`a =(ma_(0)cos30^(0)-mg sin 30^(0))/(m)`
`a = (ma_(0)(sqrt(3))/(2)-mg"(1)/(2))/(m)=g((sqrt3-1)/(2))`
from `s =ut + (1)/(2) at^(2), l_(0) = (1)/(2) at^(2)`
`l_(0) = (1)/(2) g ((sqrt3-1)/(2))t^(2) rArrt = sqrt((4l_(0))/(g (sqrt3-1)))sec` .
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