A `2kg` block is in contact with a vertical wall having coefficient of friction `0.5` between the surfaces. A horizontal force of `40N` is applied on the block at right angles to the wall. Another force of `15N` is applied on the plane of the wall and at right angles to `40N` force. Find the acclecration of the block .

Explanation

To solve the problem of finding the acceleration of the block, we can follow these steps:

### Step 1: Identify the forces acting on the block
- The block has a weight acting downwards, which can be calculated as:
\[ W = m \cdot g = 2 \, \text{kg} \cdot 9.8 \, \text{m/s}^2 = 19.6 \, \text{N} \]
- There is a horizontal force of \( F_1 = 40 \, \text{N} \) acting on the block towards the wall.
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