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A block of mass 4kg is placed on a rough...

A block of mass `4kg` is placed on a rough horizontal plane A time dependent horizontal force `F =kt` acts on the block `(k =2N//s)`. Find the frictional force between the block and the plane at `t =2` seconds and `t =5` seconds `(mu =0.2)` .

Text Solution

Verified by Experts

Given `F =kt`
When `t =2sec, F =2(2) =4N …..case (i)`
`f_(ms)=*_(s)mg= 0.2 xx 4 xx 10 =8N`
Here `F lt F_(ms) :.` friction =applied force `=4N`
When `t =5 sec, F =2 (5) =10N….case (ii)`
`F gtf :. ` frictional force `lt8N` .
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