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A block on table shown in is just on the...

A block on table shown in is just on the edge of slipping Find the coefficient of static friction between the blocks and table
.

Text Solution

Verified by Experts

`f_(1) =T sin theta`
`mu mg =T sin theta….(1)`
`80 = T cos theta…..(2)`
`(T sin 30^(@))/(T cos30^(@)) = (mumg)/(80),`
`Tan 30^(@) = (mu40)/(80) , (1)/(sqrt3) = (mu)/(2) rArr mu =(2)/(sqrt3) = 1.15` .
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Knowledge Check

  • The system shown is just on the verge of slipping. The coefficient of static friction between the block and the table top is :

    A
    0.5
    B
    0.95
    C
    0.15
    D
    0.35
  • A block of mass 1kg is at rest on a horizontal table. The coeficient of static friction between the block and the table is 0.5 . The magnitude of the force acting upward at an angle of 60^(@) from the horizontal that will just start the block moving is.

    A
    5N
    B
    `(20)/(2+sqrt3)N`
    C
    `(20)/(2-sqrt3)N`
    D
    10N
  • A block of mass m is in contact with the cart C as shown in The coefficient of static friction between the block and the cart is mu The acceleration a of the cart that will prevent the block from falling satisfies .

    A
    `agt(mg)/(mu)`
    B
    `agt(g)/(mum`
    C
    `agt(g)/(mu)`
    D
    `alt(g)/(mu)`
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