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A 30kg box has to move up an inclined pl...

A `30kg` box has to move up an inclined plane of slope `30^(@)` the horizontal with a unform velocity of `5 ms^(-1)`. If the frictional force retarding the motion is `150N`, the horizontal force required to move the box up is `(g =ms^(-2))` .

Text Solution

Verified by Experts

The force required to move a body up an inclined plane is
`F =mg sin● + f_(k)`
`f_(k) = mu_(k) (mg cos theta + P sin theta) =150 N`
`=30 (10) sin_(30^(@)) + 150 = 300N`
If `P` is the horizontal force `F=P cos●`
`P= (F)/(cos^(●)) = (300)/(cos30^(@)) (300xx2)/sqrt3 = 200sqrt3 = 346N`
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