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The apparent weight of a man in a lift i...

The apparent weight of a man in a lift is `W_(1)` when lift moves upwards with some acceleration and is `W_(2)` when it is accerating down with same acceleration. Find the true weight of the man and acceleration of lift .

A

`(W_(1)+W_(2))/(2)`

B

`(W_(1)+W_(2))/(2)`

C

`2W_(1)`

D

`2W_(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
`w_(1) =m(g +a),w_(2) =mg(g -a), w_(3) =mg`
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