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A mass of M kg is suspended by a weightl...

A mass of M kg is suspended by a weightless string. The horizontal force that is required to displace it until the string makes an angle of `45^@` with the initial vertical direction is

A

`Mg`

B

`(Mg)/(sqrt2)`

C

`Mg(sqrt2+1)`

D

`sqrt2Mg`

Text Solution

Verified by Experts

The correct Answer is:
A

`"Tan" theta = (F)/(mg)`
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