When a force F acs on a body of mass m the acceleration product in the body is a . If htree equal forces `F_(1)=F_(2)=F_(3)=F` act on the same body as shown in figure the accleration produced is

Options

A. `(sqrt2 -1)a`
B. `(sqrt2 +1)a`
C. `sqrt2a`
D. a

Answer

A

Explanation

`a = (F)/(m), F_(R) = (sqrt(F_(1)^(2) +F_(2)^(2))-F_(3)),a^(1)=(F_(R))/(m)`