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Two blocks of masses m and M are placed ...

Two blocks of masses m and `M` are placed on a horizontal frictionless table connected by light spring as shown in figure. The Mass M is pulled to the right with a force `F` It the acceleration of mass m is a then the acceleration of `M` will be .

A

`((F-ma))/(M)`

B

`((F+ma))/(M)`

C

`(F)/(M)`

D

`(am)/(M)`

Text Solution

Verified by Experts

The correct Answer is:
A
Form mass 'm' ,`F^(1) ma^(1)`
For mass `'M' F - F^(1) = Ma^(1)`
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