A shell is fired from the ground at an angle `theta` with horizontal with a velocity 'v'. At its highest point it breaks into two equal fragments. if one fragment comes back through its initial line of motion with same speed then the speed of the second fragment will be .

Options

A. `3v cos theta`
B. `3v cos theta//2`
C. `2v cos theta`
D. `sqrt3v cos theta//2`

Answer

A

Explanation

`"mu" =m_(1) v_(1) + m_(2) v_(2) 38. m_(1) v_(1) =m_(2) v_(2), (s_(1))/(s_(2)) = ((v_(1))/(v_(2)))^(2)`