Two particles of masses `m_(1)` and `m_(2)` in projectile motion have velocities `vec(v)_(1)` and `vec(v)_(2)` , respectively , at time `t = 0`. They collide at time `t_(0)`. Their velocities become `vec(v')_(1)` and `vec(v')_(2)` at time ` 2 t_(0)` while still moving in air. The value of `|(m_(1) vec(v')_(1) + m_(2) vec(v')_(2)) - (m_(1) vec(v)_(1) + m_(2) vec(v)_(2))|`

Options

A. zero
B. `(m_(1)+m_(2))"gt"_(0)`
C. `2(m_(1)+m_(2))"gt"_(0)`
D. `(1)/(2)(m_(1)m_(2))"gt"_(0)`

Answer

C

Explanation

`mv^(1) =m(u +at)`
`m_(1)v _(1)^(1) + m_(2) v_(2)^(1) = m[v_(1)+2"gt"_(0)]+m[v_(2)+2"gt"_(0)]`