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Two masses M(1) and M(2) connected by me...

Two masses `M_(1)` and `M_(2)` connected by means of a string which is made to pass over light, smooth pulley are in equilibrium on a fixed smooth wedge as shown in figure. If `theta =60^(@)` and `alpha =30^(@)` then the ratio of `M_(1)` to `M_(2)` is
.

A

`1:2`

B

`2:sqrt3`

C

`1:sqrt3`

D

`sqrt3:1`

Text Solution

Verified by Experts

The correct Answer is:
C
`m_(1)g sin theta = m_(2) g sin alpha`
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