A body is released from the top of a smooth inclined plane of inclination `theta`. It reaches the bottom with velocity `v`. If the angle of inclina-tion is doubled for the same length of the plane, what will be the velocity of the body on reach ing the ground .

Options

A. `v`
B. `2v`
C. `(2 cos theta)^(1/2) v`
D. `(2 cos theta)^(1/2) v`

Answer

C

Explanation

`v =sqrt(2glsin theta),v^(1)=sqrt(2glsin2theta)`
`F_(UP) = mg (sin theta +mu_(k) cos theta)` .