Home
Class 11
PHYSICS
A boy of mass 50kg is standing on a weih...

A boy of mass `50kg` is standing on a weihing machine placed on the floor of a lift. The machine reads his weight in newtons. The reading of the machine if the lift is moving upwards with uniform speed of `10ms^(-1)` .

A

`510N`

B

`480N`

C

`490N`

D

`500N`

Text Solution

Verified by Experts

The correct Answer is:
C
When lift moves up or down with uniform speed The apparent weight = real weight
`W =mg` .
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • NEWTONS LAWS OF MOTION

    NARAYNA|Exercise LEVEL -III|31 Videos

  • NEWTONS LAWS OF MOTION

    NARAYNA|Exercise NCERT BASED QUESTION|33 Videos

  • NEWTONS LAWS OF MOTION

    NARAYNA|Exercise LEVEL -I (C.W)|47 Videos

  • MOTION IN A STRAIGHT LINE

    NARAYNA|Exercise Level 2 H.W|29 Videos

  • OSCILLATIONS

    NARAYNA|Exercise EXERCISE - IV|41 Videos

Similar Questions

Explore conceptually related problems

A person is standing on a weighing machine placed near a door. What would be the effect on the reading of the machine if a person pulls downwards ?

A woman weighing 50 kgf stands on a weighing machine placed in lift. What will be the reading of the machine, when the lift is (i) moving upwards with a uniform velocity of 5ms^(-1) and (ii) moving downwards with a uniform acceleration of 1ms^(-2) ? Take g = 10 ms^(-2) .

A person is standing on a weighing machine placed near a door. What would be the effect on the reading of the machine if a person presses the edge of the door upward?

A 80 kg man is standing on a weightless weighing machine as shown in the figure if mass of hanging block is 40 kg, then reading of weighing machine, is

A man of mass 75kg stands on a weighing machine in a lift which is moving upwards with uniform acceleration 1.2m s^(-2) ,find the reading of weighing machine.

A man of mass m is standing on the floor of a lift. Find his apparent weight when the lift is moving upwards with uniform acceleration a.

A block of mass m kg is kept on a weighing machine in an elevator. If the elevator is retarding upward by a ms^(-2) , the reading of weighing machine is (in kgf)

A man of mass 60kg is standing on a weighing machine placed in a lift moving with velocity 'v' and acceleration 'a' as shown in figure. Calculate the reading of weighing machine in following situation : ( g = 10 m//s^(2) ) a=0, v = 0

A man of mass 60kg is standing on a weighing machine placed in a lift moving with velocity 'v' and acceleration 'a' as shown in figure. Calculate the reading of weighing machine in following situation : ( g = 10 m//s^(2) ) a = 2m//s^(2) , v = 2 m//s

A man of mass 60kg is standing on a weighing machine placed in a lift moving with velocity 'v' and acceleration 'a' as shown in figure. Calculate the reading of weighing machine in following situation : ( g = 10 m//s^(2) ) a = 2m//s^(2) ,v = 0

Home
Profile