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A block is sliding along an inclined pla...

A block is sliding along an inclined plane as shown in figure . If the acceleration of chamber is `a` as shown in figure. The time required to cover a distance `L` along inclined is

A

`sqrt((2L)/(g sin theta-a cos theta))`

B

`sqrt((2L)/(g sin theta+a sin theta))`

C

`sqrt((2L)/(g sin theta+a cos theta))`

D

`sqrt((2L)/(g sin theta))`

Text Solution

Verified by Experts

The correct Answer is:
C
`f_("net")(downward) =mg sin theta + ma cos theta`
` =m (g sin theta + a cos theta)`
`:.g_(eff) = g sin theta + a cos theta, T = sqrt((2L)/(g_(ef))` .
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