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Two masses each equal to m are lying on ...

Two masses each equal to m are lying on x-axis at `(-a,0)(+a,0)` respectively as shown in figure They are connected by a light string A force F is applied at the origin along vertical direction As a result the masses move toward each other without loosing contact with ground What is the acceleration of each mass? Assume the instantanceous position of the masses as`(-x,0)`and `(x,0)`

A

`(2F)/(F)(sqrt((a^(2)-x^(2))))/(x)`

B

`(2F)/(m)(x)/sqrt((a^(2)-x^(2)))`

C

`(F)/(2m)(x)/sqrt((a^(2)-x^(2)))`

D

`(F)/(m)(x)/sqrt((a^(2)-x^(2)))`

Text Solution

Verified by Experts

The correct Answer is:
C

`F = 2T sin theta, ma^(1) =T cos theta`
.
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