A body slides over an inclined plane of forming an angle of `45^(@)` with the horizontal. The distance x travelled by the body in time t is described by the equation `x=kt^(2)` where `k=1.732`. The coefficinet of friction between the body and the plane has a value .

Options

A. `mu =0.5`
B. `mu =1`
C. `mu =0.25`
D. `mu =0.75`

Answer

A

Explanation

Differentiating the equation `x =kt^(2)` we get the value of `a =g (sin theta -mu_(k) cos theta)` .