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Under to action of constant force F =10 ...

Under to action of constant force `F =10` N, a body moves in a straight line so that the relation between the distance `S` moved by the body and the time t is described by the equation `S =A -Bt +Ct^(2)` Find the mass of the body if `C =1 m//s^(2)` .

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The correct Answer is:
532
Given `S = A - Bt + Ct^(2),`
`:.a=(d^(2)s)/(dt^(2)) =2C =2m//s^(2)"since"F=ma`
`rArrm=(F)/(a) =(10)/(2) = 5 kg` .
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