Figure shown a block of mass m placed on a smooth wedge of mass M. Calculate the minimum value of M' and tension in the string, so that the block of mass m will move vertically downwards with acceleration `10ms^(-2)`

Answer

2

Explanation

Acceleration to the given problem, m is a freely falling body i.e Contact force between `M` and m is zero Under this condition acceleration of `M` leftwords will be `a = g cot theta = g xx sqrt3`
tension `T =Ma = (1)/(5sqrt3) xx sqrt3g =2N` .