(i)(-2i)((1)/(6)i)

Simplify : {:((i),3(6+6i)+i(6+6i),(ii),(1-i)-(-3+6i)),((iii),((1)/(3)-(2)/(3)i)-(4+(3)/(2)i),(iv),{((1)/(5)+(7)/(5)i)-(6+(1)/(5)i)}-((-4)/(5)+i)):}

The value of (i^(5)+i^(6)+i^(7)+i^(8)+i^(9))/(1+i) is (1)/(2)(1+i)(b)(1)/(2)(1-i)(c)1(d)(1)/(2)

Convert the following in the form of (a+ib) : (i) (1+i)^(4) (ii) (-3+(1)/(2)i)^(3) (iii) (1-i)(3+4i) (iv) (1+i)(1+ 2i)(1+ 3i) (v) (3+5i)/(6-i) (vi) ((2+3i)^(2))/(2+i) (vii) ((1+ i)(2+i))/((3+i)) (viii) (2-i)^(-3)

Convert the following in the form of (a+ib) : (i) (1+i)^(4) (ii) (-3+(1)/(2)i)^(3) (iii) (1-i)(3+4i) (iv) (1+i)(1+ 2i)(1+ 3i) (v) (3+5i)/(6-i) (vi) ((2+3i)^(2))/(2+i) (vii) ((1+ i)(2+i))/((3+i)) (viii) (2-i)^(-3)

Perform the indicated operations and write the result in the form x+iy: (i) (-3+2i)+(-6+3i) (ii) ((1)/(2)+(7)/(2)i)-(4+(5)/(2)i) (iii) (1-2i)-i+(4-7i)-2i+(5i+3) .

Write the following in the form x+iy: (i) (3+2i)(2-i) (ii) 2i^(2)+6i^(3)+3i^(16)-6i^(19)+4i^(25) . (iii) ((3-2i)(2+3i))/((1+2i)(2-i)) .

What is the value of (2+8i)(1-4i)-(3-2i)(6+4i)?

Given that, z=(1+2i)/(1-i)=((1+2i)(1+i))/((1-i)(1+i))