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Two thin roads are moving perpendicularl...

Two thin roads are moving perpendicularly as shown in the figure. If the friction acting between them is `F_(R )` then the unit vector in the direction of friction force acting on the rod lying along x-axis is

A

`((-hat(i)-2hat(j)))/(sqrt(5))`

B

`((hat(i)+2hat(j)))/(sqrt(5))`

C

`((3hat(i)+2hat(j)))/(sqrt(3))`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
A
Relative velocity of rod on y-axis with respect to x-axis is `vhat(i)+2vhat(j)`
The direction of friction on rod along x-axis is along relative velocity `hat(f)=(hat(i)+2hat(j))/(sqrt(5))`
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