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A block of mass m is gradually released ...

A block of mass `m` is gradually released so that at position shown it is in equilibrium with spring extended by `10 cm`. The static and kinetic coefficients of friction differ by `0.1`. When the spring is cut, `m` slide down with acceleration `( "in" ms^(-2))`

A

`0.8`

B

`1`

C

`1.8`

D

`2.1`

Text Solution

Verified by Experts

The correct Answer is:
B
`mg sin theta-mu_(k) mg cos theta = kx=mgx ( ":' k=mg)`

`mg sin theta-mu_(k)mg cos theta=ma (a)/(g) - x=0`
`(a)/(g)=0.1 rArr a = 1ms^(-2)`
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