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A block A of mass m is over a plank B of...

A block `A` of mass `m` is over a plank `B` of mass `2m`. Plank `B` si placed over a smooth horizontal surface. The coefficient of friction between `A` and `B` is `(1)/(2)`. Blocks `A` is given a velocity `V_(0)` towards right. Then

A

Acceleration of `A` is `(g)/(2)`

B

Acceleration of `A` is `g`

C

Acceleration of `B` relative to `A` is `(3)/(4)g`

D

Acceleration of `A` is zero

Text Solution

Verified by Experts

The correct Answer is:
A, C
Force of friction between the two will be maximum i.e., `mu mg`
Retardation of `A` is `a_(A) = (mu mg)/(m) = mu g`
and acceleration of `B` is `a_(B) = (mu mg)/(2m) = (mu g)/(2)`
`therefore` Acceleration of `B` relative to `A` is
`a_(BA) = a_(A)+a_(B) = (3 mu g)/(2)` substituting `mu = (1)/(2)a_(BA) = (3g)/(4)`.
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  • A block A of mass m is placed over a plank B of mass 2m. Plank B is placed over a smooth horizontal surface. The coefficient of friction between A and B is (1)/(2) block A is given a velocity v_(0) towards right. Accelration of B relative to A is

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