System is in equilibrium

Options

A. Minimum coefficent of friction required between `6 kg` block and ground `mu=2` such that system is in equilibrium.
B. Compression of vertical spring is `(2g)/(K_(1))`
C. Elongation of vertical spring is `(6g)/(K_(1))`
D. for `mu=1` system can be in equilibrium

Answer

A, B

Explanation

`F.B.D` of `6 kg` blocks

`K_(1)x=2g , K_(2)x=8g`
`N+K_(2)x sin 37^(@)=6g+K_(1)x`
`N+(8g)(3)/(5)=6g+2g , N=8g-(24g)/(5)`
`N=(16)/(5)g K_(2)x cos 37^(@)=f , 8gxx(4)/(5)= muxx(16)/(5)g 2=mu`