Home
Class 11
PHYSICS
In the above diagram calculate frictiona...

In the above diagram calculate frictional force acting on `6 kg` block

Text Solution

Verified by Experts

The correct Answer is:
6
Acceleration of system is `(10)/(10)=1`

`f=6N`
Promotional Banner

Topper's Solved these Questions

  • FRICTION

    NARAYNA|Exercise Passage type of questions I|6 Videos

  • FRICTION

    NARAYNA|Exercise Passage type of questions|6 Videos

  • COLLISION

    NARAYNA|Exercise Level-II (H.W)|54 Videos

  • GRAVITATION

    NARAYNA|Exercise EXERCISE -IV|40 Videos

Similar Questions

Explore conceptually related problems

The frictional force acting on 1 kg block is

Find fiction force acting on 2 kg block.

Friction force acting on the block is?

Calculate F such that frictional force acting on all blocks zero.

Three blocks of masses 3 kg, 6 kg and 1 kg are connected by a string passing over two smooth pulleys attached at the two ends of the horizontal surface. If the co-efficient of friction between the block and the surface is 0.6, the frictional force acting on the block of mass 6 kg is

A block of mass 1 kg is placed on a truck which accelerates with acceleration 5ms^(-2) . The coefficient of static friction between the block and truck is 0.6. The frictional force acting on the block is

In the diagram shown coefficient of friction between 2 kg block and 4 kg block is mu =0.1 and between 4 kg and ground is mu =0.2 then answer the following quwstions .(tis time) The graph of frication force acting on 4 kg block and ground as a function of time

A force of 100N is applied on a block of mass 3 kg as shown in the figure-2.164. The coefficient of friction between the surface and the block is 0.25.The frictional force acting on the block is: (Take g=10m/s^(2) )

A block of mass 0.1 kg is held against a wall by applying a horizontal force of 5 N on the block. If the coefficient of friction between the block and the wall is 0.5, then the magnitude of the frictional force acting on the block is

The friction acting on the upper block is