Home
Class 11
PHYSICS
Cube of mass m kept on rough horizontal ...

Cube of mass `m` kept on rough horizontal surface. Two insects each mass `m`. Moving in the cube with equal acceleration. `a_(0)` from `D` to `E` and `H` to `F` what is the frictional force by ground on the tube.

A

`(m+2m)a_(0)`

B

`(sqrt(5))/(sqrt(2))ma_(0)`

C

`2ma_(0)`

D

`Ma_(0)sqrt(2)`

Text Solution

Verified by Experts

The correct Answer is:
B

`f_(x)=(ma_(0))/(sqrt(2))f_(z)=2m(a_(0))/(sqrt(2))`

`f=sqrt((f_(x))^(2)+f_(y)^(2))=ma_(0) (sqrt(5))/(sqrt(2))ma_(0)`
Promotional Banner

Topper's Solved these Questions

  • FRICTION

    NARAYNA|Exercise Multiple answer question|20 Videos
  • FRICTION

    NARAYNA|Exercise Passage type of questions|6 Videos
  • COLLISION

    NARAYNA|Exercise Level-II (H.W)|54 Videos
  • GRAVITATION

    NARAYNA|Exercise EXERCISE -IV|40 Videos

Similar Questions

Explore conceptually related problems

A block of mass 1 kg in kept on a rough horizontal surface with mu_(s)=0.1 . A force of 0.5 N is applied as shown in the figure. What is the frictional force applied by ground on the block?

A body of mass 10 kg lies on a rough horizontal surface. When a horizontal force of F newtons acts on it, it gets an acceleration of 5 m//s^(2) . And when the horizontal force is doubled, it gets an acceleration of 18 m//s^(2) . The coefficient of friction between the body and the horizontal surface is

A body of mass m is kept on a rough horizontal surface of friction coefficient m . A force P is applied horizontally , but the body is not moving .Find the net force F excerted by the surface on the body .

In the adjacent figure, a uniform cube of mass m and edge l=2m is lying at rest an a rough horizontal surface. A small ball of mass m hits the cbe at its top edge with horizontal speed v_(0) and sticks to it. Friction is so large that the cube can rotate about the edge 'O' without sliding. Calculate the minimum value of v_(0) ( in m/s) so that the cube will topple. Ignore any loss of energy due to friction at the edge O and take sqrt(2)-1=0.4 .

A plank of mass M is placed on a rough horizontal force F is applied on it A man of mass m rens on the plank find the acceleration of the man so that the plank does not move on the surface . The coefficent of friction between the plank and the surface is mu Assume that the man does not slip on the plank

A block of mass m is kept on a rough horizontal surface. It is moved through a distance (s) by applyig a force F in the horizontal direction. What is the work done by the normal reaction?

A block of mass m is placed on a rough horizontal surface. If minimum force to pull the block is (mg)/(2) then coefficient of friction is :

A block of mass 70kg is kept on a rough horizontal surface (mu=0.4) . A person is trying to pull the block by applying a horizontal force, but the block is not moving. The net contact force exerted by the surface on the block is F , then: