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A long chain of mass of mass M length L ...

A long chain of mass of mass `M` length `L` is being pulled with constant velocity on a rough incline with coefficient of friction `mu`. What rate frictional force on chain is increasing

A

`(3)/(10)mu(M)/(L)gv`

B

`(5)/(6)mu(M)/(L)gv`

C

zero

D

`mu(M)/(L)gv`

Text Solution

Verified by Experts

The correct Answer is:
A

In a small time let `dx` length crossing from lower incline to upper incline
`df=mu(M(dx))/(L)g cos 37^(@)-mu (M)/(L)dx cos 60^(@)`
`df=mu(M)/(L)g (cos 37-cos 60^(@))dx`
`(df)/(dt)=(muM)/(L)g((4)/(5)-(1)/(2))(dx)/(dt)=(3)/(10)(muM)/(L)gv`
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