Home
Class 11
PHYSICS
The force acting on the block of mass 1 ...

The force acting on the block of mass `1 kg` is given by `F=5-2t`. The frictional force acting on the block after time `t=2` seconds will be: `(mu=0.2)`

A

`2N`

B

`3N`

C

`1N`

D

zero

Text Solution

Verified by Experts

The correct Answer is:
A

`f_("max")=10xx0.2=2N`
Initial force`=5N gt 2N`
`:.` block will move with acceleration
`a=(5-2t-f_(max))/(1)=5-2t-2`
`(dv)/(dt)=3-2t` , `v=3t-t^(2)`
(`because` at `t=0, v=0`) `v=0 rArrt=0, 3 sec`
`:.` at `t=2 sec` block is moving
`:. f_("max")` will act, i.e., frictional force acting `=2N`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • FRICTION

    NARAYNA|Exercise Multiple answer question|20 Videos

  • FRICTION

    NARAYNA|Exercise Passage type of questions|6 Videos

  • COLLISION

    NARAYNA|Exercise Level-II (H.W)|54 Videos

  • GRAVITATION

    NARAYNA|Exercise EXERCISE -IV|40 Videos

Similar Questions

Explore conceptually related problems

Friction force acting on the block is?

The frictional force acting on 1 kg block is

Knowledge Check

  • The force acting on the block is given by F = 5 - 2t . The frictional force acting on the block after time t = 2 seconds will be: ( mu = 0.2)

    A
    2 N
    B
    3 N
    C
    1 N
    D
    Zero

  • The friction force acting on the block at time t = 4 s will be

    A
    `50 N`
    B
    `30 N`
    C
    `25 N`
    D
    None

  • Find fiction force acting on 2 kg block.

    A
    10 N
    B
    2N
    C
    8N
    D
    0N

    • Similar Questions

    Explore conceptually related problems

    A block of mass 4kg is placed on a rough horizontal plane A time dependent horizontal force F =kt acts on the block (k =2N//s) . Find the frictional force between the block and the plane at t =2 seconds and t =5 seconds (mu =0.2) .

    A block of mass 10 kg is moving on a rough surface as shown in figure. The frictional force acting on block is :-

    In the above diagram calculate frictional force acting on 6 kg block

    A block of mass 4 kg is placed on a rough horizontal force plane. A time dependent horizontal force F = k t acts on the block. Here k = 2 Ns^(-1) . The frictional force between the block and plane at time t = 2 s is (mu = 0.2)

    A block of mass 20 kg is acted upon by a force F=30N at an angle 53^@ with horizontal in downward direction as shown. The coefficient of friction between the block and the forizontal surface is 0.2 . The friction force acting on the block by the ground is (g=10(m)/(s^2) )

    Home
    Profile