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A block of mass 2 kg is placed on the fl...

A block of mass `2 kg` is placed on the floor of an elevator. The elevator is moving with an acceleration of
`6hat(i)+7hat(j)m//s^(2)`. If `●=0.5, g =10ms^(-2)`
and horizontal, vertically upward direactions are taken as `+ve x,y` axes, find frictional force actiong on the block.

A

`12 N`

B

`16 N`

C

`10 N`

D

`17 N`

Text Solution

Verified by Experts

The correct Answer is:
A
Normal force
`N=m[g+a_(y)]=2[10+7]=34N`
limiting friction
`f_(L)=* N=0.5xx34=17N`
horizontal force on the block
`f = m xx a_(x) = 2 xx 6 = 12`.
As `f lt f_(L)`, block will be at rest w.r.t. elevator and the friction is `12 N` only.
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