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A stationary body mass m is slowly lower...

A stationary body mass `m` is slowly lowered onto a rough massive plat from moving at a constant velocity `v_(o)=4m//s`. On smooth surface. The distance the body will slide with respect to the plat from `(mu=0.2)` is:

A

`4m`

B

`6m`

C

`12m`

D

`8m`

Text Solution

Verified by Experts

The correct Answer is:
A
With respect to platform the initial velocity of the body of mass `m` is `4m//s` towards left and it starts retarding at the rate of `a=2m//s^(2)`
Using `v^(2)=u^(2)+2as` we get:
`0^(2)=4^(2)+2(-2)(s)rArrs=4"meter"`
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