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In the diagram shown the ground is smoot...

In the diagram shown the ground is smooth and `F_(1) & F_(2)` are both horizontal forces. The mass of the upper blocks is `10 kg` while that of lower block is `15 kg`. The correct statement is:

A

`m_(1)` experiences frictional force towards west only if `F_(1) gt F_(2)`

B

If `F_(1)!=F_(2)` then it is possible to keep the system in equilibrium for certain suitable values of `F_(1) & F_(2)`

C

If the system is to remain in equilibrium then `F_(1)` must be equal to `F_(2) & F_(2) lt 10 N`

D

If `(F_(1))/(m_(1))=(F_(2))/(m_(2))`, then frictional force between the blocks is zero

Text Solution

Verified by Experts

The correct Answer is:
C
If `F_(1) & F_(2)` are not zero then friction force on `m_(1)` acts west wards & on `m_(2)` acts east wards. For `m_(1)` to be in equilibrium `F_(1)-f=0` For `m_(2)` to be in equilibrium
`F_(2)-f=0rArrF_(1)=F_(2)=f` But
`f le 10N`. Hence `F_(1)=F_(2) & F_(2) le 10N`
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