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`mu` is coefficient of friction between all surface. Block `A` is kept of over block `B` on inclined plane. The minimum force required such that `'A'` block can accelerate along applied force is `mg sin theta+ n mug cos theta` calculate `n`.

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The correct Answer is:
5
Frictional force developed in all surface is limiting
`F+3 mg sin theta + 3 mu mg cos theta = 2T` …(i)
`T-2mg sin theta - 3 mu m g cos theta - mu mg cos theta = 0`
`T = 2 mg sin theta + 4 mu mg cos theta` ….(ii)
Solving the equation
`F = m g sin theta + 5 mu mg cos theta`
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