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A metal piece of mass 120g is stretched ...

A metal piece of mass `120g` is stretched to form a plane rectangular sheet of area of cross section `0.54m^2`. If length and breadth of this sheet are in the ratio `1:6`, find its moment of inertia about an axis passing through its centre and perpendicular to its plane.

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Mass =`M=120 g =120xx10^(-3) kg`
Area `=lb=0.054 m^(2) rArrrArrb/6.b=0.54 ( :' l=b/6)`
`b^(2)=0.54xx6rArrb=sqrt(3.24)=1.8 m`
`I=(M(l^(2)+b^(2)))/12=33.3xx10^(-3) kgm^(3)`
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