[" Shortest distance between the lines "],[(x-3)/(1)=(y-8)/(4)=(z-3)/(22)" and "],[(x+3)/(1)=(y+7)/(1)=(z-6)/(7)" is "k sqrt(30)" then "k=]

The shortest distance between the lines (x-3)/(3)=(y-8)/(-1)=(z-3)/(1) and (x+3)/(-3)=(y+7)/(2)=(z-6)/(4) is

Find the shortest distance between the lines (x-3)/(3)=(y-8)/(-1)=(z-3)/(1) and (x+3)/(-3)=(y+7)/(2)=(z-6)/(4)

The shortest distance between the lines (x-3)/(3)=(y-8)/(-1)=(z-3)/(1)and(x+3)/(-3)=(y+7)/(2)=(z-6)/(4) is

The shortest distance between line (x-3)/(3)=(y-8)/(-1)=(z-3)/(1) and (x+3)/(-3)=(y+7)/(2)=(z-6)/(4) is

Find the shortest distance between the lines (x+3)/(-4) =(y-6)/(3)=(z)/(2) " and " (x+2)/(-4) =(y)/(1)=(z-7)/(1)

Find the shortest distance between the lines (x+3)/(-4) =(y-6)/(3)=(z)/(2) " and " (x+2)/(-4) =(y)/(1)=(z-7)/(1)

If the shortest distance between the lines (x-3)/(3)=(y-8)/(-1)=(z-3)/(1) and (x+3)/(-3)=(y+7)/(2)=(z-6)/(4) is lambdasqrt(30) unit, then the value of lambda is