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From a complete ring of mass M and radiu...

From a complete ring of mass `M` and radius `R`, a `30^@`sector is removed. The moment of inertia of the incomplete ring about an axis passing through the centre of the ring and perpendicular to the plane of the ring is
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Text Solution

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Mass of incomplete ring `M=-M/(2pi)xx(pi)/6=(11M)/12`

`M.I.` of incomplete ring `I=[(11M)/2]R^(2)=11/12 MR^(2)`
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