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A flywheel of mass 25 kg has a radius of...

A flywheel of mass `25 kg` has a radius of `0.2 m`. It is making 240 rpm. What is the torque necessary to bring it to rest in `20 s` ? If the torque is due to a force applies tangentially on the rim of the wheel, what is the magnitude of the force ? Assume that mass of flywheel is concentrated at its rim.

Text Solution

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`alpha=(2pin)/t=(2pixx4)/20`
Torque `tau=Ialpha=(MR^(2))/2 alpha=0.2 pi Nm`
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