A thin uniform rod of length `L` is bent at its mid point as shown in the figure. The distance of the centre of mass from the point `O` is

Options

A. `L/2 sin (theta/2)`
B. `L/2 cos(theta/2)`
C. `L/4 sin (theta/2)`
D. `L/4 cos (theta/2)`

Answer

D

Explanation

`x_(cm)=(-m/2(L//4)-m/2(cos theta)L//4)/m`
`y_(cm)=(m/2sin theta(L//4))/m,r_(cm)=sqrt(x_(cm)^(2)+y_(cm)^(2))`