Let k be an integer such that the triangle with vertices `(k, -3k), (5, k)` and (-k, 2) has area 28 sq units. Then, the orthocentre of this triangle is at the point

Let k be an integer such that the triangle with vertices (k ,-3k),(5, k) and (-k ,2) has area 28s qdot units. Then the orthocentre of this triangle is at the point : (1) (1,-3/4) (2) (2,1/2) (3) (2,-1/2) (4) (1,3/4)

Let k be an integer such that the triangle with vertices (k ,-3k),(5, k) and (-k ,2) has area 28s qdot units. Then the orthocentre of this triangle is at the point : (1) (1,-3/4) (2) (2,1/2) (3) (2,-1/2) (4) (1,3/4)

Let k be an integer such that the triangle with vertices (k ,-3k),(5, k) and (-k ,2) has area 28s qdot units. Then the orthocentre of this triangle is at the point : (1) (1,-3/4) (2) (2,1/2) (3) (2,-1/2) (4) (1,3/4)

Let k be an integer such that the triangle with vertices (k ,-3k),(5, k) and (-k ,2) has area 28s qdot units. Then the orthocentre of this triangle is at the point : (1,-3/4) (2) (2,1/2) (3) (2,-1/2) (4) (1,3/4)

Let k be an integer such that the triangle with vertices (k,-3k),(5,k) and (-k,2) has area 28sq. units.Then the orthocentre of this triangle is at the point: :(1,-(3)/(4))(2)(2,(1)/(2))(3)(2,-(1)/(2))(4)(1,(3)/(4))

Area of the triangle with vertices (k,0),(1,1) and (0,3) is 5 sq. units. Find the values of k.

IF the area of a triangle with vertices (-3,0) (3,0) and (0,k) is 9 sq units. Then find k.

If the area of triangle with vertices (-3,0), (3,0) and (0,k) is 9 sq . units then the value of k is