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The angular displacement of a particle i...

The angular displacement of a particle is given by `theta =t^3 + t^2 + t +1` then,the angular acceleration of the particle at `t=2` sec is …….`rad s^(-2)

A

`14`

B

`16`

C

`18`

D

`24`

Text Solution

Verified by Experts

The correct Answer is:
A
`alpha=(domega)/(dt)=6t+2=12+2=14 rad s^(-2)`
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