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Four point size bodies each of mass `M` are fixed at four corners of a light square frame of side length `L`. The moment of inertia of the four bodies about an axis perpendicular to the plane of frame and passing through its centre is

A

`4ML^(2)`

B

`2sqrt(2)ML^(2)`

C

`2ML^(2)`

D

`sqrt(2)ML^(2)`

Text Solution

Verified by Experts

The correct Answer is:
C


`I=Sum mr^(2)`
Here `r=L/(sqrt(2))`
`:. I=4[M(L/(sqrt(2)))]=2ML^(2)`
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