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Four identical particles each of mass `m` are arranged at the corners of a square of side length `l`. If the masses of the particles at the end of a side are doubled, the shift in the centre of mass of the system.

A

`0.375 m`

B

`0.25 m`

C

`0.125 m`

D

`0.475 m`

Text Solution

Verified by Experts

The correct Answer is:
D

shift =`(md)/(M+m)`
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