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M is mass and R is radius of a circular ...

`M` is mass and `R` is radius of a circular ring. The moment of inertia of same ring about an axis in the plane of ring at a perpendicular distance `2R/3` from centre of ring is

A

`(2MR^(2))/3`

B

`(4MR^(2))/9`

C

`(3MR^(2))/8`

D

`(17 MR^(2))/18`

Text Solution

Verified by Experts

The correct Answer is:
D

`I=I_(c)=+Md^(2), I_(C)=MR^(2)` and `d=(2R)/3`
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