`I` is moment of inertia of a thin circular plate about its natural axis. The moment of inertia of a circular ring whose mass is half of mass of plate but radius is twice the radius of plate about an axis passing through any tangent of ring in its plane is

Options

A. `3I`
B. `4I`
C. `6I`
D. `1.5 I`

Answer

C

Explanation

`I=(MR^(2))/2, I_(1)=3/2M_(1)R_(1)^(2)=3/2[M/2][2R]^(2)=6I`