Three point sized bodies each of mass `M` are fixed at three corners of light triangular frame of side length `L`. About an axis perpendicular to the plane of frame and passing through a corner of frame the moment of inertia of three bodies is

Options

A. `(2mL^(2))/3`
B. `(3ML^(2))/2`
C. `(4mL^(2))/3`
D. `(3mL^(2))/4`

Answer

B

Explanation

`I=2I_(1)+I_(2) , I_(1)=(mL^(2))/3, I_(2)=I_(c)+md^(2)`
`I_(c)=(mL^(2))/12` and `d=(sqrt(3)L)/2`