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Two particles of masses `2kg` and `3kg` are projected horizontally in opposite directions from the top of a tower of height `39.2m` with velocities `5m//s` and `10m//s` respectively. The horizontal range of the centre of mass of two particles is

A

`8sqrt(2) m` in the direction of `2 kg`

B

`8sqrt(2) m` in the direction of `3 kg`

C

`sqrt(8)m` in the direction of `2 kg`

D

`sqrt(8) m` in the direction of `3 kg`

Text Solution

Verified by Experts

The correct Answer is:
B
Range of `C.M. =v_(cm)sqrt((2h)/g)`
But `v_(cm)=(m_(1)v_(1)+m_(2)v_(2))/(m_(1)+m_(2))`
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